`sin^4 theta=3/8-1/2cos2theta+1/8cos 4theta`

Prove the following : sin^4theta=3/8-1/2 cos2theta+1/8 cos4theta

If theta be any real, prove that : cos4 theta=1-8 sin^2 theta cos^2 theta =1-8 cos^2 theta +8 cos^4 theta .

Prove that, 8 sin^(4) theta = 3 - 4 cos 2 theta + cos 4 theta

If |(1+sin^2 theta,sin^2 theta,sin^2 theta),(cos^2 theta,1+cos^2 theta,cos^2 theta),(4sin 4 theta,4sin4theta,1+4sin4theta)|=0, then ... sin 4theta equal to ....

The value (2cos theta-1)(2cos2 theta-1)(2cos4 theta-1)(2cos8 theta-1)=

sin 7 theta * sin theta+sin11theta * sin 3theta= A) sin 4 theta * sin 10theta B) cos 4 theta * cos 10 theta C) sin 8 theta * sin 4 theta D) cos 8 theta * cos 14 theta

Simplify: (sin8 theta cos theta-sin6 theta cos3 theta)/(cos2 theta cos theta-sin3 theta sin4 theta)

Prove that 8 sin^4(theta/2)-8sin^2(theta/2)+1=cos2theta

If tan theta=1 then (8sin theta +5 cos theta)/(sin^3theta-2cos^3theta+7cos theta)=

If (sin theta+cos theta)/(sin theta-cos theta)=3 and theta is an acute angle, then the value of (3sin theta+4cos theta)/(8cos theta-3sin theta) is: यदि (sin theta+cos theta)/(sin theta-cos theta)=3 तो (3sin theta+4cos theta)/(8cos theta-3sin theta) का मान ज्ञात करें ।