suppose you want to cool 0.25 kg of cola (mostly water ), at `25^(@)C` by adding ice initially at `-20^(@)C`. How much ice should you add so that the final temperature will be `0^(@)C` with all the ice melt? Neglect the heat capacity of the container. specific heat of ice is` 2000 Jkg^(-1)K^(-1)`. [take specific heat of cola `4160 Jkg^(-1)K^(-1)`.]

What would be the final temperature of the mixture when 1kg of ice at -10^(@)C is mixed with 4.4kg of water of 30^(@)C ? (Specific heat capacity of ice =2100Jkg^(-1)K^(-1))

A glass beaker contains 200g of carbonated water initially at 20^(@)C . How much ice should be added to obtain the final temperature of 0^(@)C with all ice melted, if the initial temperature of ice is -10^(@)C . Neglect heat capacity of glass. [Take, C_("water")= 4190J//kg^(@)C , C_("ice") = 2100J//Kg^(@)C, L_(P) = = 3.34 xx 10^(5)J//Kg ]

The temperature of 300 g of water at 40^@ C is lowered to 0^@ C by adding ice to it. Find the mass of ice added if specific heat capacity of water is 4.2 J g^(-1) K^(-1) and specific latent heat of ice is 336 J g^(-1)

When a 0.45 kg of ice at 0^(@)C mixed with 0.9 kg of water at 55^(@)C in a container, the resulting temperature is 10^(@)C . Calculate the heat of fusion of ice. Specific heat of water is 4186 j kg^(-1) K^(-1) .

Find the amount of heat required to convert 10 kg ice at -10^(@)C to water at 50^(@)C . Given specific heat of ice 2100Jkg^(-1)K^(-1) , specific heat of water 4200Jkg^(-1)K^(-1) and latent heat of ice 3.36xx10^5Jkg^(-1)

On mixing 0.35 kg of ice at 0^@C with 0.8 kg of water at 45^@C in a container, the final temperature becomes 20^@C . What will be the heat of fusion of ice? (Specific heat of water = 4186 J kg^(-1) K^(-1) )

The water equivalent of a calorimeter is 10g and it contains 50 g of water at 15^(@)C . Some amount of ice, initially at -10^(@)C is dropped in it and half of the ice melts till equilibrium is reached. What was the initial amount of ice that was dropped (when specific heat of ice =0.5"cal"gm^(-1)""^(@)C^(-1) specific heat of water =1.0"cal"gm^(-1)""^(@)C^(-1) and laten heat of melting of ice =80"cal"gm^(-1) )?

How much boiling water at 100^@C Is needed to melt 2 kg of ice is that the mixture which is all water is at 0^@C ? [Specific heat capacity of water = 4.2 JK^(-1) and specific latent heat of ice = 336 Jg^(-1) ]

What will be the result of mixing 2kg of cooper at 100^(@)C with 0.75 kg of ice at 0^(@)C (Specific heat capacity of cooper =378J kg^(-1)K^(-1) specific heat capacity of water =4200 J kg^(-1)K^(-1) and specific latent heat of fusion of ice =336xx10^(3)Jkg^(-1) )