`underset(x to oo)"Lt" ((x^(2)+2x-1)/(2x^(2)-3x-2))^((2x+1)/(2x-1))=`

underset(x to oo)"Lt" 1/x^(2)=

Find the limits : underset(x to oo)lim ((1+x)/(2+x))^((1-sqrtx)//(1-x)) (b) underset(x to oo)lim ((x^(2)+2x-1)/(2x^(2)-3x-2))^((2x+1)//(x-1))

underset(x to oo)"Lt" ((x^(2)+5x+3)/(x^(2)+x+2))^(x)=

underset(x to 0)"Lt" (e^(2x) +sinx-1)/x

underset(x to 1)"Lt" (x^(2)-1)/(|x-1|=

underset(x to oo)lim (3x^(2)+5x+2)/(2x^(2)-3x+1)=

underset(x to oo)lim (|3x^(2)+1|)/(2x^(2)+1)=

underset(x to oo)lim (3x^(3)+x^(2)-1)/(x^(2)-x+7)=

underset(x to 1)"Lt" ((2x-3)(sqrtx-1))/(2x^(2)+x-3)=

underset(x to 0)"Lt" (1-cos 2x^(@))/(x^(2))=