Write the normal form of the equation of the plane `2x-3y+6z+14=0.`

Change to normal form the plane 2x-3y+6z+4=0

Write the equation of the plane 3x-4y+z+5=0 in normal form.

Find the equation of the plane through the intersection of the planes 2x - 3y + z - = 0 and x - y + z + 1 = 0 and perpendicular to the plane x + 2y - 3z + 6 = 0.

Write the symmetric form of equation of the following lines : 3x-2y+z=1,5x-4y-6z=2.

Find the equation of the plane passing through the intersection of the planes 2x-3y+z-4=0 and x-y+z+1=0 and perpendicular to the plane x+2y-3z+6=0

The normal unit vector of the plane x-3y + 2z = 6 is ............