Recommended Questions
- " EXAMPLE "1" (i) "lim(x rarr pi)(sin x)/(pi-x)
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- lim(x->pi)(sin(pi-x))/(pi(pi-x))
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- lim (x rarr (pi ^ (+)) / (4)) [cos (x- (pi) / (4))] ^ ((1) / (sin (x- ...
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- lim(x->pi)(sin(pi-x)/(pi(pi-x)))
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- lim(x->(pi/2)) (1-sinx)tanx =
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- lim (x rarr (pi) / (2)) [sin x] is
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- lim(x->pi/2){(1-sinx)tanx}
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- lim (x rarr0) (sin x sin ((pi) / (3) + x) sin ((pi) / (3) -x)) / (x)
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- lim (x rarr pi) ([sin x] + x) is
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