Recommended Questions
- |{:(3x^2,3x,1),(x^2+2x,2x+1,1),(2x+1,x+2,1):}|=(x-1)^3
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- [[3x^2, 3x,1],[ x^2 + 2x, 2x + 1, 1],[2x+1,x+2,1]]=(x-1)^3
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- Simplify: (x^3-2x^2+3x-4)(x-1)-\ (2x-3)(x^2-x+1)
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- 3 ((3x-1) / (2x + 3))-2 ((2x + 3) / (3x-1)) = 5, x! = (1) / (3),-(3) /...
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- 3 ((3x-1) / (2x + 3))-2 ((2x + 3) / (3x-1)) = 5, x! = (1) / (3),-(3) /...
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- Without expanding a determinant at any stage, show that |{:(x^(2)...
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- " If " |{:(x^(2)+x,,x+1,,x-2),(2x^(2)+3x-1,,3x,,3x-3),(x^(2)+2x+3,,2x...
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- (2x^(3)+3x^(2)-3)/(2x^(2)-x-1)
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- |{:(3x^2,3x,1),(x^2+2x,2x+1,1),(2x+1,x+2,1):}|=(x-1)^3
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