Arrange the following radicals in decreasing order of their stability.
(I) `overset(*)(C)H_(3)`
(II) `CH_(3)-overset(*)(C )H_(2)`
(III)

Arraange the follwooing carbanions in decreasing order of their stability : I. CH -= overset( -)(C ) II. CH_(3) - C -= overset( - ) ( C ) III. CH_(2) = overset(- )( C ) H IV. CH_(3) - overset( - )( C ) H_(2) The correct choice is :

Arraange the follwooing carbanions in decreasing order of their stability : I. CH -= overset( -)(C ) II. CH_(3) - C -= overset( - ) ( C ) III. CH_(2) = overset(- )( C ) H IV. CH_(3) - overset( - )( C ) H_(2) The correct choice is :

Arrange the following in decreasing order of their stability :- (I) CH_(3)-overset(oplus)(CH_(2)) " "(II) CH_(3)-underset(CH_(3))underset(|)overset(oplus)(CH) (III) CH_(3)-underset(oplus)overset(CH_(3))overset(|)(C)-CH_(3) " "(IV) {:(CH_(2)-overset(o+)(C)H_(2)),(|),(F):}

Arrange the following in correct order of their stability ? (I) CH-=overset(Theta)C " "(II) CH_(2)=overset(Theta)CH " "(III) CH_(3)-overset(Theta)CH_(2)

Arrange the following increasing order of number of hyperconjugation structures. (I) CH_(3)-overset(.)(C)H-CH_(3) (II) CH_(3)-overset(CH_(3))overset(|)CH-overset(.)(C)H-CH_(3) (III) CH_(3)-overset(CH_(3))overset(|)underset(.)C-CH_(3)

Arrange the following anions in increasing order of stability and give reasons: CH_(2)=overset(Theta)(C)H,CH_(3)overset(Theta)(C)H_(2),CH-=overset(Theta)(C)