A charge q enters into a magnetic field (B) perpendicularly with velocity V. The time rate of work done by the magnetic force on the charge is

The work done by a magnetic field on moving charge is

A particle of mass m and charge q enters a magnetic field B perpendicularly with a velocity v , The radius of the circular path described by it will be

What is the work done by a magnetic field on a moving charge?

An electron with charge e enters a uniform. magnetic field vec B with a velocity vec V . The velocity is perpendicular to the magnetic field. The force on the charge e is given by abs(vecF) = B ev Obtain the dimensions of vec B .

Write the expression for Lorentz magnetic force on a particle of charge q moving with velocity oversetrarrV in a magnetic field oversetrarrB . Show that no work is done by this force on the charged particle.

A positive charge particle of charge q, mass m enters into a uniform magnetic field with velocity v as shown in the figure . There is no magnetic field to the left of PQ . Find (i) time spent, (ii) distance travelled in the magnetic field (iii) inpulse of magnetic force.