हल कीजिए : `x+y=8,x-y+2=0`

Find the value of X and Y (X और Y का मान ज्ञात कीजिए) I. 2x^(2)-5x-3=0 II. 4y^(2)+16y+15=0

Find the value of X and Y (X और Y का मान ज्ञात कीजिए) I. x^(2)+9x+20=0 II. y^(2)+7y+12=0

Find the value of X and Y (X और Y का मान ज्ञात कीजिए) I. x^(2)+13x+42=0 II. y^(2)+16y+63=0

Find the value of X and Y (X और Y का मान ज्ञात कीजिए) I. x^(2)-14x+48=0 II. y^(2)+6=5y

Minimum distance between y^2-4x - 8y +40 =0 and x^2 - 8x-4y +40=0 is

From the point A (0, 3) on the circle x^2+4x+(y-3)^2=0 a chord AB is drawn & extended to a M point such that AM=2AB. The equation of the locus of M is: (A) x^2 +8x+y^2 =0 (B) x^2+8x+(y-3)^2=0 (C) (x-3)^2+8x+y^2=0 (D) x^2+8x+8y^2=0

find x and y : 2x+3y-8=0, 3x+y-5=0

2x + 3y = 8 , x - 2y + 3 = 0