A piece of wood was found to have `C^(14)//C^(12)` ratio 0.6 times that in a living plant. Calculate that in a living plant. Calculate the period when the plant died. (Half life of `C^(14) = 5760` years)?

A piece of wood was found to have C^(14)/C^(12) ratio 0.7 times that in a living plant.Calculate the period when the plant died. Half-life of C^(14)= 5760 years

A piece of wood is found to have the (C^(14))/(C^(12)) ratio to be 0.5 times of that in a living plant The number of years back the plant died will be ( T of C^(14)=5,580 years)

A piece of charcoal from the ruins of a settlement in Japan was found to have .^(14)C// .^(14)C ratio what was 0.617 times that found in living organisms. How old is the piece of charcol? ( t_(1//2) for .^(14)C is 5770 year?)

An archaeological substance contained wood had only 66.66% of C^14 found in a tree. Calculate the age of the sample if the half life of C^14 Is 5730 years.

The amount of ._(6)C^(14) isotope in a piece of wood is found to be one-fifth of that present in a fresh piece of wood. Calculate the age of wood (Half life of C^(14) = 5577 years)

The amount of ._(6)C^(14) isotope in a piece of wood is found to be one-fifth of that present in a fresh piece of wood. Calculate the age of wood (Half life of C^(14) = 5577 years)