Equation of het hyperbola whose vertices are `(+-3,0)` and foci at `(+-5,0)` is a.`16 x^2-9y^2=144` b. `9x^2-16 y^2=144` c. `25 x^2-9y^2=225` d. `9x^2-25 y^2=81`

Equation of the hyperbola whose vertices are (+-3,0) and foci at (+-5,0) is a. 16 x^2-9y^2=144 b. 9x^2-16 y^2=144 c. 25 x^2-9y^2=225 d. 9x^2-25 y^2=81

Equation of het hyperbola whose vertices are (+-3,0) and foci at (+-5,0) is 16x^(2)-9y^(2)=144 b.9x^(2)-16y^(2)=144c25x^(2)-9y^(2)=225d.9x^(2)-25y^(2)=81

The foci of the hyperbola 9x^2-16 y^2=144 are

For the hyperbola 9x^2-16y^2=144 .find the vertices, foci and eccentricity

The equation of the tangent to the hyperbola 16x^(2)-9y^(2)=144 at (5,8//3) , is

The equation of the tangent to the hyperbola 16x^(2)-9y^(2)=144 at (5,8//3) , is

The equation of the ellipse whose vertices are (9,2),(-1,2) and the distance between the foci is 8 unit is (A)9(x-3)^(2)+25(y-4)^(2)=225(B)9(x+3)^(2)+25(y+4)^(2)=225(C)9(x-4)^(2)+25(y-3)^(2)=225(D)9(x+4)^(2)+25(y+3)^(2)=225