Show that the line represented by equation `x=ay+b,z=cy+d` in symmetric form is`(x-b)/a=y/1=(z-d)/c`

Write the equation of the line x=ay+b,z=cy+d in symmetric from.

If the equation of line is x = ay + b : z = cy +d. Then its symmetric form is

If the equation of the line is x-ay+b=0 ; z-cy+d=0 .Then its symmetric form is

The dr's of the line x=ay+b,z=cy+d are

If the two lines represented by x+ay=b,z+cy=d and x=a'y+b', z=c'y+d' be perpendicular to each other, then the value of a a'+c c' is :

The equation of the line x+y+z-1=04x+y-2z+2=0 written in the symmetrical form is

The cartesian equations of a line are x= ay+b,z= cy+d . Find its direction ratios.

If the lines x=ay +b, z=cy+d and x=a'y + b', z=c'y + d' are perpendicular, then

Prove that the lines x=ay +b,z =cy +d and x=a'y +b' z =c'y +a' are perpendicular if aa'+cc' +1=0

Prove that if the lines x = ay + b, z = cy + d and x = a'y + b', z = c'y + d' are perpendiclar to each other aa' + cc' + 1 = 0.