Calculate (i) kinetic energy (ii) potential energy and (iii) total energy of a satellite of mass `200 kg` orbiting around the earth in an orbit of height `100 km` from the surface of earth. Given, mass of earth `= 10^(25) kg`,radius of earth `= 6.4 xx 10^(6) m, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2)`.

If a spaceship orbits the earth at a height of 500 km from its surface, then determine its (i) kinetic energy, (ii) potential energy, and (iii) total energy (iv) binding energy. Mass of the satellite = 300 kg, Mass of the earth = 6xx10^(24) kg , radius of the earth = 6.4 xx 10^(6) m, G=6.67 xx 10^(-11) "N-m"^(2) kg^(-2) . Will your answer alter if the earth were to shrink suddenly to half its size ?

If a spaceship orbits the earth at a height of 500 km from its surface, then determine its (i) kinetic energy, (ii) potential energy, and (iii) total energy (iv) binding energy. Mass of the satellite = 300 kg, Mass of the earth = 6xx10^(24) kg , radius of the earth = 6.4 xx 10^(6) m, G=6.67 xx 10^(-11) "N-m"^(2) kg^(-2) . Will your answer alter if the earth were to shrink suddenly to half its size ?

What is the gravitational potential due to the Earth at a point which is at a height of 2RE above the surface of the Earth, Mass of the Earth is 6xx10^24 kg, radius of the Earth = 6400 km and G = 6.67xx10^(-11) Nm^2 kg^(-2) .

The potential energy os a body of mass 100 kg is circulating in orbit at a height of 600 km above the surface of earth is (Radius of earth 6400 km, mass of earth =6xx10^(24)" kg and G"=2//3xx10^(-10)Nm^(2)//kg^(2))

Calculate the gravitational potential energy of a body of mass 30 kg , at a height of 4 R from the surface of Earth, where R (= 6.4 xx 10^(6) m) is the radius of the Earth. Mass of the Earth = 6.0 xx 10^(24) kg, G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

Calculate the height above the earth at which the geostationary satellite is orbiting the earth. Radius of earth = 6400km. Mass of earth = 6 xx 10^(24) kg. G = 6.67 xx 10^(-11) Nm^(2) kg^(-2) .

What is magnitude of gravitational force between the earth and a 1 kg object on its surface ? Take mass of earth to be 6 xx 10^24 kg and radius of the earth is 6.4 xx 10^6 m.G =6.67 xx10^-11nm^2kg^-2 .

Calculate the force of gravitation due to earth on a ball of 1 kg mass lying on the ground.(Mass of earth =6xx10^(24) kg Radius of earth =6.4xx10^(3) km and G=6.7xx10^(-11)Nm^(2)/Kg^(2)