The mass of the Earth is `6 xx 10^(24)` kg and its radius is 6400 km. Find the acceleration due to gravity on the surface of the Earth.

If the mass of the earth is 6xx10^(27) g and its radius 6400 km, what will be the acceleration due to gravity at a height 64 km above the earth's surface ? Given that G=6.67xx10^(-8) CGS unit.

Calculate the value of the universal gravitational constant from the given data. Mass of the Earth = 6xx10^24 kg, Radius of the Earth = 6400 km and the acceleration due to gravity on the surface = 9.8 m//s^2

Assuming the mass of Earth to be ten times the mass of Mars, its radius to be twice the radius of Mars and the acceleration due to gravity on the surface of Earth is 10 m//s^(2) . Then the accelration due to gravity on the surface of Mars is given by

Assuming the mass of Earth to be ten times the mass of Mars, its radius to be twice the radius of Mars and the acceleration due to gravity on the surface of Earth is 10 m//s^(2) . Then the accelration due to gravity on the surface of Mars is given by

The mass of a planet is 4 times the mass of the earth and its radius is 2 times the radius of the earth. The acceleration due to gravity on that planet is

Find the magnitude of the acceleration due to gravity at the surface of the earth. ( M = 6 xx 10^(24) Kg, R = 6400 Km)