In a `DeltaABC,` show that `r_(1)* r_(2)* r_(3)*r=Delta^(2).`

Show that rr_(1)r_(2)r_(3)=Delta^(2)

In DeltaABC, " show that " (ab-r_(1)r_(2))/(r_(3))=(bc-r_(2)r_(3))/(r_(1))=(ca-r_(3)r_(1))/(r_(2))

Show that r r_1 r_2 r_3 = Delta^2

In DeltaABC, if r_(1) lt r_(2) lt r_(3) then

In Delta ABC , show that: (r_(1)+r_(2)) sec^(2) ""(C)/(2) = (r_(2) +r_(3)) sec^(2) ""(A)/(2) =(r_(3)+r_(1)) sec^(2)""(B)/(2)

In a DeltaABC, r_(1) + r_(2) + r_(3) -r =

In a DeltaABC, r_(1) + r_(2) + r_(3) -r =

In DeltaABC , If r_(1)=21, r_(2)=24, r_(3)=28 , then