In a horizontal pipeline of uniform cross section the pressure falls by `8 N//m^(2)` between two points separated by `1 km`. If oil of density `800 kg//m^(3)` flows through the pipe, find the change in `KE` per kg of oil at these points.

In a horizontal pipe line of uniform cross-section, pressure falls by 5 Pa between two points separated by 1 km. The change in the kinetic energy per kg of the oil flowing at these points is (density of oil =800kgm^(-3))

Oil of density 800 kg/m^3 is flowing through a horizontal pipe line. At two points separated by a distance of 1km pressure difference is 5 N/m^3 . Calculate the change in KE per kg of the oil flowing at these points.

Water is flowing steadily through a horizontal pipe of non-uniform cross-section. If the pressure of water is 4 xx 10^4 N//m^2 at a point where cross-section is 0.02 m^2 and velocity of flow is 2 m//s . What is the pressure at a point where cross-section reduces to 0.01 m^2 ? .

Water flowing steadily through a horizontal pipe of non-unifrom cross-section. If the pressure of water is 4xx10^(4)N//m^(2) at a point where cross-section is 0.02 m^(2) and velocity of flow is 2 ms^(-1) . The pressure at a point where cross-section reduces to 0.01 m^(2) is 3.4xx10^(n) Pa. What is the value of n ?

In a horizontal oil pipeline of constant cross-sectional area the pressure decrease between two point 300 km apart is 5000 pascal (1 pascal = 1 newton per square meter). What is the loss of energy per unit volume per unit distance? [Hint : Loss in energy =(P_(1))/(rho)-(P_(2))/(rho) because (P)/(rho) is pressure energy per unit mass and loss in energy per unti volume =P_(1)-P_(2) .]