x और y के लिये हल कीजिए :
`(x)/(a) +(y)/(b)=a + b`
`(x)/(a^(2)) +(y)/(b^(2)) = 2`

(x)/(a)+(y)/(b)=a^(2)+b^(2) and (x)/(a^(2))+(y)/(b^(2))=a+b

Solve: (x)/(a)+(y)/(b)=a^(2)+b^(2) and (x)/(a^(2))+(y)/(b^(2))=a+b

2(x/a)+(y/b)=2; (x/a)-(y/b)=4

If x/a + y/b = a+b and x/a^(2) + y/b^(2) =2 , then what is x/a^(2) - y/b^(2) equal to?

If a : b = x : y , then show that (a^(2) + b^(2)) : a^(3)/(a + b) : : (x^(2) + y^(2)) : x^(3)/(x + y)

The foci of hyperbola xy = ((a^2 + b^2)/(4)) are given by (A) x = y = +- ((a^2 + b^2)/(4a)) (B) x = y = +- ((a^2 + b^2)/(4b)) (C) x = y = +- ((a^2 + b^2)/(2a)) (D) x = y = +- ((a^2 + b^2)/(2b))

If a=(x)/(x+y) and b=(y)/(x-y), then (ab)/(a+b) is equal to (a) (xy)/(x^(2)+y^(2)) (b) (x^(2)+y^(2))/(xy)( c) (x)/(x+y) (d) ((y)/(x+y))^(2)

Solve: (a - b )x + (a + b)y = a^(2) - 2ab - b^(2) and (a + b) (x + y) = a^(2) + b^(2)