The equations of the perpendicular bisector of the sides AB and perpendicular bisector of the sides AB and AC of a `triangle ABC` are x-y + 5 = 0 and x + 2y = 0 respectively, if the point Ais (1,-2), then the equation ofthe line BC is

Explanation

equation for AB is `y +2= -1(x-1)`

`y+x+1=0` (1)

equation of AC is `y+2=2(x-1)`

`y-2x+4=0` (2)

the other bisectors line is `x-y+5=0 & x+2y=0` (3) & (4)

putting values from`(4) to (2)`

we get `5y=-4`

`y=-4/5 & x=8/5`

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