Solve the cryptarithm: `B A x\ \ B3 5\ \ 7A`

Explanation

`BAxxB3 = 57A`

If we multiply any number `x` with 3 and we get a number `x` in unit digit, then `x` is either `5` or `0`.

So, in the given question, `A` can be `5` or `0`.

If, `A` is `5`, then, the result is `575`.

Then, `3**B+1` can be `7`.

So, `B` can be `2`.

If we try `A=3` and `B=2`, it satisfies our multiplication. So, this is the right answer.