There is KI and sucrose solution with 0.1 M concentration, if the osmotic pressure of KI and sucorse solution is 0.465 atm and 0.245 atm respectively. Then find the van't Hoff factor of KI and its degree of dissociation.

There is AP_(3) and sucrose solution with 0.1 M concentration each . If osmotic pressure of AB_(3) and sucrose solution is 0.72 atm and 0.24 atm respectively at same temperature . The fraction of AB_(3) dissociated will be :

Kl and sucrose solutions with 0.1 m concentration have osmotic presure of 0.465 atm and 0.245 atm respectively find alpha of Kl

The osmotic pressures of 0.010 M solutions of KI and sucrose ( C_(12)H_(22)O_(11) ) are 0.432 atm and 0.24 atm respectively. The van't Hoff factor for KI is :

The osmotic pressures of 0.010 M solutions of KI and sucrose ( C_(12)H_(22)O_(11) ) are 0.432 atm and 0.24 atm respectively. The van't Hoff factor for KI is :

The osmotic pressures of 0.010 M solutions of KI and sucrose ( C_(12)H_(22)O_(11) ) are 0.432 atm and 0.24 atm respectively. The van't Hoff fector for KI is :

The osmotic pressures of 0.010 M solutions of KI and of sucrose (C_(12)H_(22)O_(11)) are 0.432 atm and 0.24 atm respectively. The vant's Hoff factor for KI is:

The osmotic pressure of 0.010 M solutions of Kl and of sucrose (C_(12)H_(22)O_(11)) are 0.432 atm and 0.24 atm respectively . The van't Hoff factor for Kl is :

The Van't Hoff factor for 0.1 M CaCl_(2) solution is 2.74. The degree of dissociation is