Henry law constant for oxygen dissolved in water is` 4.34 xx 10^(4) atm` at `25^(@) C`. If the partial pressure of oxygen in air is 0.4 atm.Calculate the concentration ( in moles per litre) of the dissolved oxygen in equilbrium with air at `25^@C`.

The Henry's Law constant for oxygen dissolved in water is 4.34xx10^(4) atm at 25^(@)C . If partial pressure of exygen in are is 0.2 atm. Under ordinary atmospheric conditions, calculate the concentration (in moles/litre) of dissolved oxygen in water in equilibrium with air at 25^(@)C .

The Henry's Law constant for oxygen dissolved in water is 4.34 xx 10 ^(4)atm ( mol /L) at 25^(@) C . If the partial pressure of oxygen in air is 0.2 atm under ordinary atmospheric condition calculate the concentration (in mol/litre ) of dissolved oxygen in water equilibrium with air at 25^(@) C

The K_H for the solution of oxygen dissolved in water is 4xx 10^(4) atm at a given temperature . If the partial pressure of oxygen in air is 0.4 atm the mole fraction of oxygen in solution is

The partial pressure of oxygen in air is 0.2 atm. What is the conentration of dissolved oxygen in water in equilibrium with air at 25^(@) C ? ( K_(H) for oxgyen at 25^(@)C is 4.34 cc 10^(4) atm).

The osmotic pressure of a sugar solution at 24^(@)C is 2.5 atm . The concentration of the solution in mole per litre is