If ` sin2A= lambda sin 2B` prove that `(tan(A+B)/tan(A-B))=(lambda+1)/(lambda-1)`

If sin2A=lamdasin2B .Prove that tan(A+B)/(tan(A-B))=(lamda+1)/(lamda-1)

If sin2A=lambdasin2B then prove that : frac(tan(A+B))(tan(A-B))=frac(lambda+1)(lambda-1)

If s in2A=lambda sin2B, then write the value of (lambda+1)/(lambda-1)

If sin A = m sin B, "prove that" "tan" (A-B)/2 = (m-1)/(m+1) "tan" (A+B)/2

If sin2A=lambdasin2B , then write the value of (lambda+1)/(lambda-1) .

If cos A+cos B=(1)/(2) and sin A+sin B=(1)/(4) prove that: tan((A+B)/(2))=(1)/(2)

Prove that: If tan A=x tan B, prove that (sin(A-B))/(sin(A+B))=(x-1)/(x+1)

If sec theta+tan theta=lambda then prove that (lambda^2-1)/(lambda^2+1)=sin theta

If tan20=lambda ,prove that (tan160^(@)-tan110^(@))/(1+tan160^(@)*tan110^(@))=(1-lambda^(2))/(2 lambda) .

If (tan3alpha)/(tanalpha)=lambda ,show that (sin3alpha)/(sinalpha)=(2lambda)/(lambda-1) and hence prove that the value of lambda does not lie between 1/3 and 3