यदि ` cos A = ( 1)/(7), cos B =(13)/( 14) ` तो सिद्ध कीजिए की `A -B =60^(@) , A ` और B धनात्मक न्यूनकोण है|

cos A = (13) / (14), cos B = (1) / (7), 0

If sin(A-B) =1/2 and cos(A+B) =1/2 , where A>B>0^@ , and A+B is an acute angle, then the value of A is: यदि sin(A-B) =1/2 and cos(A+B) =1/2 तो A+B का मान ज्ञात करें , जहाँ A>B>0^@ और A एक न्यून कोण है

If sin(A-B) =1/2 and cos(A+B) =1/2 , where A>B>0^@ , and A+B is an acute angle, then the value of A is: यदि sin(A-B) =1/2 and cos(A+B) =1/2 तो A+B का मान ज्ञात करें , जहाँ A>B>0^@ और A एक न्यून कोण है

If cos A=1/7 and cos B=13/14 (A, B being positive acute), prove that A -B = 60^@ .

If A and B are positive acute angles and cos A=(1)/(7),cos B=(13)/(14), then show that A-B=60^(@).

If sin(A+B) = cos(A-B) = sqrt3/2 and A and B are acute angles. The measures of angles A and B (in degrees) will be: यदि sin(A+B) = cos(A-B) = sqrt3/2 और A और B न्यून कोण है। A और B (डिग्री में) का मान ज्ञात करें ।

If A and B are positive acute angles and cos A = 1/7, cos B = 13/14 , then show that A-B=60^0 .

If cos A = 1/7 and cos B =""13/14 where A and B both are acute angles, then the value of (A-B) is-