`E^(c-)` for `Cr^(3+)+3e^(-) rarr Cr `and `Cr^(3+)+e^(-) rarr Cr^(2+)` are `-0.74 V` and `-0.40V`, respectively, `E^(c-)` for the reaction is `Cr^(+2)+2e^(-) rarr Cr`

If E_(1)=0.5V corresponds to Cr^(3+)+3e^(-) rarr Cr_((s)) " and " E_(2)=0.41V corresponds to Cr^(3+)+e^(-) rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+2e^(-) rarr Cr_((s)) .

If E_(1)=0.5V corresponds to Cr^(3)+3e^(-)rarr Cr_((s)) and E_(2)=0.41V corresponds to Cr^(3+)+e rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+2e rarr Cr_((s))

From the following data at 25^(@)C Cr^(3+)(aq.)+3e^(-)rarr Cr^(2+)(aq.) , E^(@)= -0.424V Cr^(2+)(aq.)+2e^(-) rarr Cr(s), " "E^(@)= -0.900V Find E^(@) at 25^(@)C for the reaction : Cr^(3+)+3e^(-) rarr Cr(s)

If E_(1)=0.5V corresponds to Cr^(3)+3e^(-)rarr Cr_((s)) and E_(2)=0.41V corresponds to Cr^(3+)+e rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+e rarr Cr^(2+) reactions, calculate the emf (E_(3)) of the reaction Cr^(2+)+2e rarr Cr_((s))

Given that the standard reduction potential (E^(@)) of Cr^(3+) | Cr and Cr^(2+) |Cr are -0.74 and -0.91 V respectively. The E^(@) of Cr^(3+) |Cr^(2+) is:

Given that the standard reduction potential (E^(@)) of Cr^(3+) | Cr and Cr^(2+) |Cr are -0.74 and -0.91 V respectively. The E^(@) of Cr^(3+) |Cr^(2+) is:

E^(@) of two reactions are given below : Cr^(3+) + 3e rarr Cr, E^(@) = -0.74 V OCl^(-) + H_(2)O + 2e rarr Cl^(-) + 2OH^(-), E^(@) = 0.94 V What will be the E^(@) for ? 3OCl^(-) + 2Cr + 3H_(2)O rarr 2Cr^(3+) + 3Cl^(-) + 6OH^(-)