The tangents to a curve at a point on it is perpendicular to the line joining the point with the origin. Find the equation of the curve.

The gradient of the tangent to the curve at a point is k times to the gradient of the straight line joining this pint and origin. Find the equation of the curve, where k(ne0) is constant.

A curve passes through the point (-2, 1) and at any point (x, y) of the curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (-4, -3). Find the equation of the curve.

At any point (x,y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (−4,−3). Find the equation of the curve given that it passes through (−2,1)

At any point (x,y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (-4,-3) . Find the equation of the curve, given that it passes through (-2,1) .

At any point (x,y) of a curve, the slope of the tangent is twice the slope of the line segment, joining the point of contact to the point (-4,-3). Find the equation of the curve given that it passes through (-2,1).

At any point (x, y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact to the point (– 4, –3). Find the equation of the curve given that it passes through (–2, 1).

At any point P(x,y) of a curve, the slope of the tangent is twice the slope of the line segment joining the point of contact P to the point (-4,-3) Find the equation of the curve given that it passes through the point (-2, 1)

At any point (x,y) of a curve,the slope of the tangent is twice the slope of the line segment joining the point of contact to the point Find the equation of the curve given that it passes through quad (-2,1)