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A body of mass 3 kg is under a constant ...

A body of mass `3 kg` is under a constant force which causes a displacement `s` metre in it, given by the relation `s=(1)/(3)t^(2)`, where `t` is in seconds. Work done by the force in 2 seconds is

A

`(8)/(3)J`

B

`(19)/(5) J`

C

`(5)/(19)J`

D

`(3)/(8)J`

Text Solution

Verified by Experts

The correct Answer is:
A
Given, `S=(1)/(3)t^(2)`
`rArr v=(dS)/(dt)=(2)/(3) t rArr a=(d^2 S)/(dt^2) = (2)/(3)`
Therefore, work `=2 xx (1)/(3) t^(2)`
At `t=2` seconds
work done `=2 xx (1)/(3) xx 2 xx 2=(8)/(3)` J.
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