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A ball is thrown up with a certain veloc...

A ball is thrown up with a certain velocity at angle `theta` to the horizontal. The kinetic energy varies with height h of the particle as:

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
D
At highest point KE is not zero so option (a) and (b) are not correct.
`therefore x = u cos theta t and h = u sin theta t - (1)/(2) gt^(2)`
`=x tan theta - (gx^(2))/(2 u^(2) cos^(2) theta)`
`therefore` From equation of motion , `v^(2) = u^(2) - 2gh`
`therefore KE= (1)/(2) mv^(2) = (1)/(2) mu^(2) - mgh rArr KE= K, - (mgh)h`
So, option ( d) is correct.
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