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A particle of mass m moves along a circu...

A particle of mass m moves along a circular path of radius r with a centripetal acceleration `a_n` changing with time t as `a_n=kt^2`, where k is a positive constant. The average power developed by all the forces acting on the particle during the first `t_0` seconds is

A

`(mrk^4)/(t_(0)^(2))`

B

`(mkrt_(0)^(2))/(2)`

C

`(mrkt_(0)^(2))/(8)`

D

`mrk^(4) t_(0)^(2))/(16)`

Text Solution

Verified by Experts

The correct Answer is:
B

Given , `a_(n) = kt^(2)`
or `(v^2)/( r) = kt^(2)` or `v^(2) = krt^(2)`
Therefore, average power delivered `=("Total work done")/("Total time elapsed")`
Or `lt P gt =((1)/(2) m(v^(2)-0^(2) ) )/( t_(0)) = (m)/(2) (krt_(0)^(2))/(t_(0)) = (mkrt_(0)^(2))/( 2)`.
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