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One gram of ice at 0^(@)C is added to 5 ...

One gram of ice at `0^(@)C` is added to 5 gram of water at `10^(@)C`. If the latent heat of ice be 80 cal/g, then the final temperature of the mixture is -

A

`-5^@ C`

B

`0^@ C`

C

`+5^@ C`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
Heat gained by ice + latent heat = heat loss by water `1 xx 80 +1 (theta -0) xx 1 = 5 xx 1 xx (10-theta )`
` 6 theta =- 30 or , theta = - 5^@ C ` not possible
`therefore ` All the ice does not melt.
` therefore ` Temperature of mixture is `0^@C .`
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