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The temperature of a body is increased b...

The temperature of a body is increased by `50%`. The amount of radiation emitted by it would be nearly

A

increase by 400%

B

decrease by 400%

C

increase by 50%

D

decrease by 50%

Text Solution

Verified by Experts

The correct Answer is:
A

Percentage increase `=(E_2 -E_1)/(E_1) xx 100`
BY stefan.s law `(E_2)/(E_1) =((T_2)/(T_1))^4`
subtract 1 from each side
`((E_2)/(E_1)-1) = ((T_2)/(T_1))^4 -1 therefore (E_2 - E_1)/(E_1) = (T_(2)^(4) - T_(1)^(4))/(T_(1)^(4))`
` therefore ` percentage increase `= (T_(2)^(4) - T_(1)^(4))/( T_(1)^(4))xx 100`
`= ((150 )^4 - (100)^4)/((100)^4 )xx 100 = 400 % `
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