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An experiment takes 10 minutes to raise ...

An experiment takes `10` minutes to raise the temperature of water in a container from `0^(@)C "to" 100^(@)C` and another `55` minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be `1 "cal//g ^(@)C`, the heat of vapourization according to this experiment will come out to be:-

A

530 cal/g

B

540 cal/g

C

550 cal/g

D

560 cal/g

Text Solution

Verified by Experts

The correct Answer is:
C
Heat given for raising the temperature of W g of water from `0^@ C ` to `100^@ C = W xx 1 xx 100 ` cal
time taken `=10 xx 60 s.`
` therefore ` Heat given per second `= (W xx 1 xx 100 )/( 10 xx 60)` cal
Heat given out to convert W g to steam `= W xx t `
this is the heat supplied in `55 xx 60 s`
` therefore `Heat given `= 100 xx W xx(55 xx 60 )/( 10 xx 60 ) =W L`
` therefore L=10 xx 55 implies L- 550 cal /g`
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