A constant force of 20N is applied to pull a body of mass 10 k, kept on a smooth horizontal surface. What is the increase in its kinetic energy if the body starts from rest and covers a distance of 5m?

A force of 20N is applied on a body of mass 5 kg resting on a horizontal plane. The body gains a kinetic energy of 10 after is moves a distance 2m. The fricitional force is

At t=0 , a force F=at^(2) is applied to a small body of mass m at an angle alpha resting on a smooth horizontal plane

At the instant t=0 , a force F=kt (k is a constant) acts on a small body of mass m resting on a smooth horizontal surface. The time, when the body leaves the surface is

At the instant t=0 , a force F=kt (k is a constant) acts on a small body of mass m resting on a smooth horizontal surface. The time, when the body leaves the surface is

A force acts for 8 s on a body of mass 5 kg at rest,on a smooth horizontal surface.The force then stops acting and the body describes 80 m in next 5 s .The force acting on body is

A force acts for 8 s on a body of mass 5kg at rest,on a smooth horizontal surface.The force then stops acting and the body describes 80m in next 5s .The force acting on body is ?

At the moment t=0 the force F=at is applied to a small body of mass m resting on a smooth horizontal plane (a is constant). The permanent direction of this force forms an angle alpha with the horizontal (figure). Find: (a) the velocity of the body at the moment of its breaking off the plane, (b) the distance traversed by the body up to this moment.

Oif a force 20 N is applied on a body of mass 5 kg at rest then find the kinetic energy of the body after 10s.

A force of 200 N is applied to a body and its velocity changes from 5m/s to 10m/s in a second. What is the mass of the body?