When burnt in air, a 12.0 g mixture of carbon and sulphur yields a mixture of `CO_2` and `SO_2` , in which the number of moles of `SO_2` is half that of `CO_2`.The mass of the carbon the mixture contains is : (At . Wt. S=32)

When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO_2 and SO_2 in the volume ratio of 2:1, volume being measured at the same conditions of temperature and pressure moles of carbon in the mixture is

When burnt in air, 14.0 g mixture of carbon and sulphur gives a mixture of CO_(2) and SO_(2) in the volume ratio of 2 : 1, volumes being measured at the same conditions of temperature and pressure. Moles of carbon in the mixture is

How would you remove CO_2 from a mixture of CO_2 and SO_2

What is the ratio of weights of O_2 and SO_2 , the mixture of which contains equal number of molecules of each gas?

What is the ratio of weights of O_2 and SO_2 , the mixture of which contains equal number of molecules of each gas?