The parametric equation of a line is given by `x=-2+(r)/(sqrt(10))` and `y=1+3(r)/(sqrt(10))` :

The parametric equation of a line is given by x=-2+(r)/(sqrt(10)),y=1+(3r)/(sqrt(10))* then the area of the triangle formed by the line with the axes is (in sq.units)

The parametric equations of the line are give by x=-2+r/(sqrt(10)) and y=1+(3r)/(sqrt(10)) then for the line

The parametric equation of a given by x=-2+(r)/(sqrt(10)) and y=1+3(r)/(sqrt(10)) then, for the line

The parametric equation of the circle x^(2)+y^(2)=r^(2) are

Find the parametric equation of the circle x^(2)+y^(2)+x+sqrt(3)y=0

The parametric equations of the circle x^(2) + y^(2) + x + sqrt(3)y = 0 are

t in R parametric equation of parabola are x=at^2 and y = 2at .

Distance between the lines represented by 9x^2-6x y+y^2+18 x-6y+8=0 , is 1/(sqrt(10)) 2. 2/(sqrt(10)) 3. 4/(sqrt(10)) 4. sqrt(10) 5. 2/(sqrt(5))

The length of latusrectum of the parabola whose parametric equations are x=t^2+t+1,y=t^2-t+1, where t in R is equal to (1) sqrt(2) (2) sqrt(4) (3) sqrt(8) (4) sqrt(6)