If accelerating potential of an alpha particle is doubled than its new debrolgie wavelength becomes

If the momentum of a particle is doubled, then its de-Broglie wavelength will

If the kinetic energy of a particle is doubled, de Broglie wavelength becomes:

If the kinetic energy of a particle is doubled, De-Broglie wavelength becomes :

Calculate the ratio of the accelerating potential required to accelerate (i) a proton and (ii) and alpha particle to have the same de-Broglie wavelength associated with them.

Through what potential difference should an electron be accelerated so that its de-Broglie wavelength becomes 0.4Å?

Through what potential difference should an electron be accelerated so that its de-Broglie wavelength becomes 0.4 overset(@)(A) ?

A proton when accelerated through a potential difference of V, has a De-Broglie wavelength lambda associated with it.if an alpha -particle is to have the same De-Broglie wavelength lambda, it must be accelerated through a potential difference of