Home
Class 12
MATHS
The pdf of a random variable X is f(x)...

The pdf of a random variable X is
`f(x)=3(1-2x^(2)),0ltxlt1`
`=0" otherwise"`
The `P((1)/(4)ltXlt(1)/(3))=` . . .

Promotional Banner

Similar Questions

Explore conceptually related problems

The p.d.f of a random variable X is given by f(x) = 3(1-2x^(2)), 0 lt x lt 1 = 0 , otherwise Find P((1)/(4)lt X lt (1)/(3))

The p.d.f of a random variable X is given by f(x) = 3(1-2x^(2)), 0 lt x lt 1 = 0 , otherwise Find P((1)/(4)lt X lt (1)/(3))

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then P((1)/(4)ltxlt(1)/(3)) =

The p.d.f. of a random variable X is f(x)=2x, 0lexle1 =0 , otherwise Then the value of P(1/3 lt X lt 1/2) is

The p.d.f. of a random variable X is f(x)=1/5, 0lexle5 =0 , otherwise Then the value of P(1 lt X lt 3) is

The p.d.f. of a r.v. X is f(x)={{:(kx","0ltxlt2),(0", otherwise"):} , then P((1)/(4)ltXlt(1)/(3)) =

The p.d.f. of a r.v. X is f(x)={{:(3(1-2x^(2))","0ltxlt1),(0", otherwise"):} , then F (x) =

The p.d.f. of a r.v. X is f_(X)(x)={{:(kx(1-x)","0ltXlt1),(0", otherwise"):} , then P((1)/(4)ltXlt(1)/(2)) =

The p.d.f. of a random variable X is (f)x=2x, 0lexle1 =0 , otherwise Then the value of P(1/3 lt X lt 1/2) is

The p.d.f. of a random variable X is (f)x=1/5, 0lexle5 =0 , otherwise Then the value of P(1 lt X lt 3) is