Express the roots of `(x+1)^3+64=0` in terms of cube roots of 1

Find the cube-roots of : 64

Let's find the cube root of 64

The cube roots of 1+I are

If a,b,c are the roots of x^(3)-3x^(2)+3x+26=0 and omega is cube roots of unity then the value of (a-1)/(b-1)+(b-1)/(c-1)+(c-1)/(a-1)=

Find the cube-roots of : 27/64

Find the cube-roots of : 64xx27

Find the cube-roots of : 64xx729

The product of the square root of x with the cube root of x is cube root of the square root of x sixth root of the fifth power of x fifth root of the sixth power of x (d) sixth root of x

Find the cube - roots of : -64xx-125

Find the cube-roots of : (-64)/343