120 g of ice at `0^(@)C` is mixed with 100 g of water at `80^(@)C`. Latent heat of fusion is 80 cal/g and specific heat of water is 1 cal/`g-.^(@)C`. The final temperature of the mixture is

150 g of ice is mixed with 100 g of water at temperature 80^(@)C . The latent heat of ice is 80 cal/g and the specific heat of water is 1 cal//g-.^(@)C . Assuming no heat loss to the environment, the amount of ice which does not melt is –

If 10 g of ice at 0^(@)C is mixed with 10 g of water at 40^(@)C . The final mass of water in mixture is (Latent heat of fusion of ice = 80 cel/g, specific heat of water =1 cal/g""^(@)C )

If 10 g of ice at 0^(@)C is mixed with 10 g of water at 40^(@)C . The final mass of water in mixture is (Latent heat of fusion of ice = 80 cel/g, specific heat of water =1 cal/g""^(@)C )

If 10 g of ice at 0^(@)C is mixed with 10 g of water at 40^(@)C . The final mass of water in mixture is (Latent heat of fusion of ice = 80 cel/g, specific heat of water =1 cal/g""^(@)C )

100g of ice at 0C is mixed with 100g of water 80C The final temperature of the mixture will be