We would like to perpare a scale whose length does not change with temperature. It is proposed to prepare a unit scale f this type whose length remains, say 10 cm. We can use a bimetallic strip made of brass and iron each of different length (both components) would change in such a way that differnece between theri lenght rermain constant. If `alpha_(iron) = 1.2 xx 10^(-5)//K and alpha_(brass) = 1.8 xx 10^(-5)//K,` what should we take as lenght of each strip ?

We would like to prepare a scale whose length does not change with temperature. It is proposed to prepare a unit scale of this type whose length remains, say 10 cm. We can use a bimetallic strip made of brass and iron each of different length whose length (both components) would change in such a way that difference between their lengths remain constant. If alpha_("iron")=1.2xx10^(-5)//K and alpha_("brass")=1.8xx10^(-5)//K what should we take as length of each strip ?

We would like to prepare a scale whose length does not change with temperature. It is proposed to prepare a unit scale of this type whose length remains, say 10 cm. We can use a bimetallic strip made of brass and iron each of different length whose length (both components) would change in such a way that difference between their lengths remains constant. If alpa_(iron = 1.2 xx 10^-5 //K and alpha_(brass = 1.8 xx 10^-5//K , what should we take as length of each strip?

What is a bimetallic strip? Why does a bimetallic strip of brass and iron bend on heating?

A bimetallic strip of brass and iron is straight at room temperature. When this bimetallic strip is heated it bends, such that:

The difference between the lengths of steel rod and a brass rod is 0.6 at all temperatures. What are their lengths at 0^@C ? (alpha_Steel = 12 xx 10^-6//^@C , (alpha_(brass)= 18 xx 10^-6//^@C )

We would like to make a vessel whose volume does not change with temperature (take a hing from the problem aobve). We can use brass and iron (beta_(brass) = 6 xx10^(-5) // K and beta_(iron) = 3.55 xx 10^(-5)//K) ot create a volume of 100 c c. How do you think you can achieve this.

The length of the steel rod which would have the same difference in length with a copper rod of length 24cm at all temperatures. (alpha_("copper") = 18 xx 10^(-6) K^(-1) alpha_("steel") = 12 xx 10^(-6) k^(-1)) is -

We would like to make a vessel whose volume does not change with temperature (take a hint from the problem above). We can use brass and iron (beta_("vbrass")=6xx10^(-5)//K" and "beta_("viron")=3.55xx10^(-5)//K) to create a volume of 100 cc. How do you think you can achieve this.

What must be the lengths of steel and copper rods at 0^(@)C for the difference in their lengths to be 10 cm at any common temperature? (alpha_(steel)=1.2xx10^(-5).^(@)K^(-1)and alpha_("copper")=1.8xx10^(-5).^(@)K^(-1))