In `HS^(-)`, `I^(-)`, `R-NH_(2)`, `NH_(3)` order of proton accepting tendency will be

In HS − ,I − ,R−NH 2 ​ ,NH 3 ​ , the order of proton accepting tendency will be:

In {:(-NO_(2),-NH_(2),-SO_(3)H),(I,II,III):} , the decreasing order of -I effect is

5.1g of solid NH_(4)HS is introduced in a 16.4 lit. vessel & heated upto 500 K K_(B) for equilibrium NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) is 0.16 . The maximum pressure developed in the vessel will be :

5.1g of solid NH_(4)HS is introduced in a 16.4 lit. vessel & heated upto 500 K K_(B) for equilibrium NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g) is 0.16 . The maximum pressure developed in the vessel will be :

One "mole" of NH_(4)HS(s) was allowed to decompose in a 1-L container at 200^(@)C . It decomposes reversibly to NH_(3)(g) and H_(2)S(g). NH_(3)(g) further undergoes decomposition to form N_(2)(g) and H_(2)(g) . Finally, when equilibrium was set up, the ratio between the number of moles of NH_(3)(g) and H_(2)(g) was found to be 3 . NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(c)=8.91xx10^(-2) M^(2) 2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g), K_(c)=3xx10^(-4) M^(2) Answer the following: To attain equilibrium, how much % by weight of folid NH_(4)HS got dissociated?

One "mole" of NH_(4)HS(s) was allowed to decompose in a 1-L container at 200^(@)C . It decomposes reversibly to NH_(3)(g) and H_(2)S(g). NH_(3)(g) further undergoes decomposition to form N_(2)(g) and H_(2)(g) . Finally, when equilibrium was set up, the ratio between the number of moles of NH_(3)(g) and H_(2)(g) was found to be 3 . NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(c)=8.91xx10^(-2) M^(2) 2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g), K_(c)=3xx10^(-4) M^(2) Answer the following: To attain equilibrium, how much % by weight of folid NH_(4)HS got dissociated?

One "mole" of NH_(4)HS(s) was allowed to decompose in a 1-L container at 200^(@)C . It decomposes reversibly to NH_(3)(g) and H_(2)S(g). NH_(3)(g) further undergoes decomposition to form N_(2)(g) and H_(2)(g) . Finally, when equilibrium was set up, the ratio between the number of moles of NH_(3)(g) and H_(2)(g) was found to be 3 . NH_(4)HS(s) hArr NH_(3)(g)+H_(2)S(g), K_(c)=8.91xx10^(-2) M^(2) 2NH_(3)(g) hArr N_(2)(g)+3H_(2)(g), K_(c)=3xx10^(-4) M^(2) Answer the following: Assuming the volume due to solid NH_(4)HS is negligible what will be the density of the gaseous mixture in the above equilibrium system?