If any `triangle ABC, tanA+tanB+tanC=6` and `tanAtanB=2`, then the values of `tanA, tanB` and `tanC` are respectively` (A) 1,2,3 (B) 3,2,1 (C) 2,1,3 (D) 1,2,0

In a triangle tanA+tanB+tanC=6 and tanAtanB=2 , then the values of tanA, tanB and tanC are

In a triangle, tanA + tanB + tanC = 6 and tanA tanB = 2 , then the values of tanA, tanB, tanC are :

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a) 1,2,3 (b) 3,2//3,7//3 (c) 4,1//2 ,3//2 (d) none of these

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a) 1,2,3 (b) 3,2//3,7//3 (c) 4,1//2 ,3//2 (d) none of these

In triangle A B C ,tanA+tanB+tanC=6a n dtanAtanB=2, then the values of tanA ,tanB ,tanC are, respectively (a)1,2,3 (b) 3,2//3,7//3 (c)4,1//2 ,3//2 (d) none of these

If in a triangle ABC,tanA+tanB+tanC=6 and tanAtanB=2, then the triangle is acute angled triangle.

In a triangle ABC, tanA+tanB+tanC=6 and tanA. tan B = 3, then find the nature of triangle.

In a triangle ABC tanA+tanB+tanC>=P then P=

In DeltaABC, if tanA+tanB+tanC=6 and tanA.tanB=2 then tanC= . .

If, in a triangleABC , tanA =1 and tanB=2, then: tanC=