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Solid Ammonium carbamate dissociates as:...

Solid Ammonium carbamate dissociates as:
`NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g).`
In a closed vessel, solid ammonium carbonate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of `NH_(3)` at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure. Also find the partial pressure of ammonia gas added.

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Solid Ammonium carbamate dissociates as: NH_(2)COONH_(4)(s)hArr2NH_(3)(g)+CO_(2)(g). In a closed vessel, solid ammonium carbamate is in equilibrium with its dissociation products. At equilibrium, ammonia is added such that the partial pressure of NH_(3) at new equilibrium now equals the original total pressure. Calculate the ratio of total pressure at new equilibrium to that of original total pressure.

A(s)hArr2B(g)+C(g) The above equilibrium was established by initially taking A(s) only. At equilibrium, B is removed so that its partial pressure at new equilibrium becomes 1//3^(rd) of original total pressure. Ratio of total pressure at new equilibrium and at initial equilibrium will be :

A(s)hArr2B(g)+C(g) The above equilibrium was established by initially taking A(s) only. At equilibrium, B is removed so that its partial pressure at new equilibrium becomes 1//3^(rd) of original total preswsure. Ratio of total pressure at new equilibrium and at initial equilibrium will be :

Solid ammonium carbamate dissociated according to the given reaction NH_2COONH_4(s) hArr 2NH_3(g) +CO(g) Total pressure of the gases in equilibrium is 5 atm. Hence K_p .

Solid ammonium carbamate dissociated according to the given reaction NH_2COONH_4(s) hArr 2NH_3(g) +CO(g) Total pressure of the gases in equilibrium is 5 atm. Hence K_p .