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Which of the following pair of graphs in...

Which of the following pair of graphs intersect? `y=x^2-xa n dy=1` `y=x^2-2xa n dy=sinx` `y=x^2-x+1a n dy=x-4`

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Which of the following pair of graphs intersect? y=x^2-xa n dy=1 y=x^2-2x +3 and y=sinx y=x^2-x+1a n dy=x-4

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Find the angle of intersection of y=a^xa n dy=b^x

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Find the angle of intersection of the following curves : y^2=xa n dx^2=y y=x^2a n dx^2+y^2=20 2y^2=x^3a n dy^2=32 x x^2+y^2-4x-1=0a n dx^2+y^2-2y-9=0 (x^2)/(a^2)+(y^2)/(b^2)=1a n dx^2+y^2=a b x^2+4y^2=8a n dx^2-2y^2=2 x^2=27ya n dy^2=8x x^2+y^2=2xa n dy^2=x y=4-x^2a n dy=x^2

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Prove that graphs of y=x^2+2a n dy=3x-4 never intersect.

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