`int (x+1) / (x^2 + 4x +5) dx`

int ( x +2)/( 2x ^(2) + 6x + 5) dx = p int ( 4x +6)/( 2x ^(2) + 6x +5) dx + (1)/(2) int (1)/( 2x ^(2) + 6x + 5) dx then p

int (2x+1)/(x^2+4x-5) dx

int (x-2)/(x^(2)-4x+5)dx=

Evaluate int(1)/(sqrt(x^2-4x+5) dx.

int(2x+1)/(x^(2)+4x-5)dx

Evaluate: int(1)/(x^(2)+4x-5)dx

int(1)/(x^(2)+4x+5)dx

int (1)/(sqrt(x^(2)-4x-5))dx=