ABC is a triangle where a=6, b=3 and `cos(A-B)=4/5`
Value of angle C is-

ABC is a triangle where a=6, b=3 and cos(A-B)=4/5 (i) Area of the triangle ABC (in sq. units) is-

(i) If a:b:c= 2:3:4 and s=27 inches, find the area of the triangle ABC. (ii) If in a triangle ABC, a=6, b=3 and cos(A-B) =4/5 then find its area.

In Delta ABC , a= 6 ,b=3 and cos (A-B) = 4/5 .Then are of triangle is

If in a triangle ABC,a=6,b=3 and cos(A-B)=(4)/(5) find the area of the triangle.

In a triangle ABC, two sides are a = 6, b = 3 and cos(A-B) =(4)/(5) then the area of the triangle is

In Delta ABC, if a = 6, b=3 and cos (A-B) = (4)/(5) " then " angle C =

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Valus of sin A is equal to

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Valus of sin A is equal to

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Valus of sin A is equal to

Let a,b, c are the sides opposite to angles A, B , C respectively in a Delta ABC tan""(A-B)/(2)=(a-b)/(a+b)cot ""C/2 and (a)/(sin A)=(b)/(sin B) =(c)/(sin C), If a=6,b=3 and cos (A-B) =4/5 Angle C is equal to