If `S =3t^(3)+9t^(2)+2t+7` , then distance travelled by the particle during the first second of its motion is

If S=(1)/(3)t^(3)-4t^(2)+12t , then distance travelled by the particle before it first comes to rest is

A particle moves in a straight line and its velocity v at time t seconds is given by v=(6t^(2)-2t+3) cm/sec. Find the distance travelled by the particle during the first 5 second after the start.

Find the distance travelled by the particle during the time t = 0 to t = 3 second from the figure .

The position of a particle moving rectilinearly is given by x = t^3 - 3 t^2 - 10 . Find the distance travelled by the particle in the first 4 seconds starting from t = 0 .

If S=2t^(3)-4t^(2)+12t , then distance travelled during the time -interval [0,1] is

A particle moves along a line by s = (t^(3))/(3) - 3t^(2) + 8t then the distance travelled by the particle before if first comes to rest is

A particle moves along a line according to the law s(t)=2t^(3)-9t^(2)+12t-4 , where tge0 . Find the total distance travelled by the particle in the first 4 seconds.

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is

A particle is moving in a striaght line and at a given time, its displacement is S = t^(3) - 6t^(2) + 9t , where t is in seconds and S is in meter . The total distance travelled by the particle during the first five seconds is

A particle moves according to the law s=t^(3)-9t^(2)+24t . The distance covered by the particle before it first comes to rest is -