KCl, NaCl प्रकार के समान जालक में क्रिस्टलीकृत होता है । दिया है `r_(Na^(+))//r_(Cl^(-)) = 0.55` तथा `r_(K^(+))//r_(Cl^(-)) = 0.74` तब KCl तथा NaCl के लिए इकाई सेल के किनारो का अनुपात ज्ञात कीजिए :

KCl crystallises in the same type of lattice as does NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.55 and r_(K^(+))//r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl is

KCl crystallises in the same type of lattices as does NaCl. Given that r_(Na^(+)) //r_(Cl^(-)) = 0.55 and r_(K^(+)) //r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl.

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55 and r_(K^(+))//r_(Cl^(-))=0.74 , the ratio of the side of unit cell for KCl to that of NaCl is

KCl crystallises in the same type of lattice as does NaCl Given that r_(Na^(+))//r_(Cl^(-))=0.55andr_(K^(+))//r_(Cl^(-))=0.74 .Calculate the ratio of the side of the unit cell for KCl to that of NaCl.

KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl: