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KCI crystallizes in the same type of lac...

`KCI` crystallizes in the same type of lacttice as does `NaCl`. Given that
`(r_(Na^(o+)))/(r_(Cl^(Θ))) = 0.5` and `(r_(Na^(o+)))/(r_(K^(o+))) = 0.7`
Calculate (a) the ratio of side of the unit cell for `KCl` to that for `NaCl`, and (b) the ratio of density of `NaCl` to that `KCl`.

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KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

KCl crystallizes int the same type of lattic as done NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.50 and r_(Na^(+))//r_(K^(+)) = 0.70 , Calcualte the ratio of the side of the unit cell for KCl to that for NaCl:

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KCl crystallises in the same type of lattice as does NaCl . Given that r_(Na^(+))//r_(Cl^(-)) = 0.55 and r_(K^(+))//r_(Cl^(-)) = 0.74 . Calculate the ratio of the side of the unit cell of KCl to that of NaCl is