If `alpha,beta,gamma` are the roots of the equation `2x^3 – x^2 + x-1=0` then `alpha^2 + beta^2 + gamma^2 =`

If alpha,beta,gamma are the roots of the equation 2x^(3) -3x^(2) +6x + 1 = 0 then alpha^(2) + beta^(2) + gamma^(2) is equal to…..

If alpha,beta,gamma are the roots of the equation 2x^(3)-3x^(2)+6x+1=0, then alpha^(2)+beta^(2)+gamma^(2) is equal to

If alpha,beta,gamma are the roots of the equation 2x^(3)-5x^(2)+3x-1=0, then (1)/(alpha beta)+(1)/(beta gamma)+(1)/(gamma alpha) is

if alpha, beta, gamma are the roots of the equation x^(3) + 3x + 2=0 " then " (alpha^(3) +beta^(3)+gamma^(3))/(alpha^(2) +beta^(2)+gamma^(2))

if alpha, beta, gamma are the roots of the equation x^(3) + 3x + 2=0 " then " (alpha^(3) +beta^(3)+gamma^(3))/(alpha^(2) +beta^(2)+gamma^(2))

If alpha , beta , gamma are the roots of x^3 +2x^2 -3x -1=0 then alpha^(-2) + beta^(-2) + gamma^(-2)=

If alpha, beta, gamma are the roots of x^(3) + x^(2) + x + 1 = 0 then (alpha - beta)^(2) + (beta - gamma)^(2) + (gamma - alpha)^(2) =

If alpha, beta, gamma are the roots of the equation x^(3) - 6x^(2) + 11x - 6 = 0 and if a = alpha^(2) + beta^(2) + gamma^(2) , b = alpha beta + beta gamma + gamma alpha and c = (alpha + beta) (beta + gamma)(gamma + alpha), then the correct inequality among the following is :

If alpha, beta ,gamma are the roots of the equation x ^(3) + 2x ^(2) - x+1 =0, then vlaue of ((2- alpha )(2-beta) (2-gamma))/((2+ alpha ) (2+ beta ) (2 + gamma)) is :