If a photoemissive surface has a threshold frequency of `3 xx 10^(14)` Hz, calculate the energy of the photons in eV.

If a photoemissive surface has a threshold frequency of . 6 xx 10^(14)Hz , calculate the energy of the photons in eV. Given h=6.6 xx 10^(-34)Js .

A photon of energy 8 eV is incident on metal surface of threshold frequency 1.6 xx 10^(15) Hz , The maximum kinetic energy of the photoelectrons emitted ( in eV ) (Take h = 6 xx 10^(-34) Js ).

A photon of energy 8 eV is incident on metal surface of threshold frequency 1.6 xx 10^(15) Hz , The maximum kinetic energy of the photoelectrons emitted ( in eV ) (Take h = 6 xx 10^(-34) Js ).

A photon of energy 10 eV is incident on a metal surface of threshold frequency 1.6 xx 10^15 Hz . The kinetic energy of the photoelectron (in eV) is (assume h = 6 x 10^-34 )

A photon of energy 8 eV is incident on a metal surface of threshold frequency 1.6 xx 10^(15) Hz , then the maximum kinetic energy of photoelectrons emitted is ( h = 6.6 xx 10^(-34) Js)

If the threshold frequency be 2 xx 10^14 Hz , the work function is